The moment of inertia of a rod of mass $M$ and length $L$ about an axis passing through its centre and perpendicular to it is $\frac{1}{12} ML^2$. The rod is bent in the middle so that the two halves make an angle of $60^o$. The moment of inertia of the bent rod about the same axis (passing through the original centre of the rod) would be:

  • A
    $\frac{1}{48} ML^2$
  • B
    $\frac{1}{12} ML^2$
  • C
    $\frac{1}{24} ML^2$
  • D
    $\frac{ML^2}{8\sqrt{3}}$

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$Assertion$ : $A$ judo fighter,in order to throw his opponent onto the mat,tries to initially bend his opponent and then rotate him around his hip.
$Reason$ : As the mass of the opponent is brought closer to the fighter's hip,the moment of inertia of the opponent about the axis of rotation decreases,which makes it easier to rotate the opponent.

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